We have the system of equations:
[tex]\begin{gathered} y=6x+11 \\ 2x-3y=7 \end{gathered}[/tex]We replace the value of y in the second equation and solve for x:
[tex]\begin{gathered} 2x-3(6x+11)=7 \\ 2x-18x-33=7 \\ -16x=7+33 \\ -16x=40 \\ x=\frac{40}{-16} \\ x=-2.5 \end{gathered}[/tex]Then, we calculate y:
[tex]y=6x-11=6\cdot(-2.5)-11=-15-11=-26[/tex]The solution is (x,y) = (-2.5, -26)
