Given data:
* The equation of the wave is,
[tex]y=4\sin (18t-10x)[/tex]
Solution:
From the equation of the wave, the angular velocity and the value of propagation constant is,
[tex]\begin{gathered} \text{angular velocity }\omega=18\text{ radian/second} \\ \text{Propagation constant k =10 radian/meter} \end{gathered}[/tex]
The value of the velocity of propagation is,
[tex]\begin{gathered} v=\frac{18}{10} \\ v=1.8\text{ m/s} \end{gathered}[/tex]
Thus, the velocity of the propagation of wave is 1.8 m/s.
