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Which of the following gives the correct phases for the products of reaction I-1?3CaCl2(aq) + 2Na3PO4--> 6NaCl + Ca3(PO4)3A. 6NaCl(aq) + Ca3(PO4)2 (aq)B. 6NaCl(s) + Ca3(PO4)2 (aq)C. 6NaCl(aq) + Ca3(PO4)2 (s)D. NaCl(s) + Ca3(PO4)2 (s)

Respuesta :

The resulting reaction products are an ionic salt (NaCl) and an oxysalt (Ca3(PO4)2.

When NaCl is in contact with water, it dissolves and the water molecules separate their ions, therefore it will be in the aqueous phase.

In contrast, Ca3(PO4)2 is not soluble in water, therefore the molecule will settle out of solution as solid crystals.

So the answer will be C. 3NaCL(aq)+Ca3(PO4)2

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