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Joanne bought 3 baseball cards for $160. If the first card was as expensive as the combined price of the second and the third cards, and the second card cost $20 more than the third card, what is the price of the first card?A. 80B. 50C. 100D. 60

Respuesta :

$80

1) In this problem, we can the following:

First + Second + Third = 160

First= Second+3rd Card

2) We can set the following:

[tex]\begin{gathered} 2x+20+\left(x+20\right)+x=160 \\ \\ 4x+40=160 \\ \\ 4x+40-40=160-40 \\ \\ 4x=120 \\ \\ \frac{4x}{4}=\frac{120}{4} \\ \\ x=30 \\ \\ First\:card: \\ \\ 2x+20 \\ \\ 2(30)+20 \\ \\ 60+20 \\ \\ 80 \\ \end{gathered}[/tex]

3) Thus, the first card cost $80

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