We are going to formulate the equation mentioned in the statement
[tex]\frac{x-3}{x+5-3}=\frac{7}{8}[/tex]Now let's solve the problem
[tex]\begin{gathered} \frac{x-3}{x+5-3}=\frac{7}{8} \\ \frac{x-3}{x+2}=\frac{7}{8} \\ 8\left(x-3\right)=7\left(x+2\right) \\ 8x-24=7x+14 \\ 8x-7x=24+14 \\ x=38 \\ \end{gathered}[/tex]Now we calculate the values for the original equation
[tex]\begin{gathered} \frac{38}{38+5} \\ \frac{38}{43} \end{gathered}[/tex]The solution would be 38/43
