Given: The
[tex]\begin{gathered} AC=12 \\ BC=13 \end{gathered}[/tex]
To Determine:
[tex]AB[/tex]
Using the Pythagoras theorem
[tex]AB^2+AC^2=BC^2[/tex][tex]\begin{gathered} AB^2=BC^2-AC^2 \\ AB^2=13^2-12^2 \\ AB^2=169-144 \\ AB^2=25 \\ AB=\sqrt[]{25} \\ AB=5 \end{gathered}[/tex]
Hence AB = 5
