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A diver jumps from a platform 25 feet above a pool. The equation that represents his fall is h (t) –16t+ 10t + 25 where h is their height and t is the time. Find the diver's height after 2 seconds.

Respuesta :

as the equation is

[tex]h(t)=-16t^2+10t+20[/tex]

We only need to replace t by 2. We get that:

[tex]h(2)=-16\cdot4+10\cdot2+25=-64+45=-19[/tex]

So his height after 2 seconds is -19 feet, so we can say he already is under the water

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