We can divide the given figure into different rectangular faces:
Faces 1 and 3 have the same measure, also 2 and 4, and faces 5 and 6.
Faces 1 and 3 have the following dimensions: L=100cm W=50cm.
Faces 2 and 4 have the following dimensions: L=100cm W=35cm.
Faces 5 and 6 have the following dimensions: L=50cm W=35cm.
The surface area of a rectangular face is given by:
[tex]SA=L*W[/tex]
Thus, the surface areas of the given faces are:
[tex]\begin{gathered} SA_1=100cm*50cm=5000cm^2 \\ SA_3=100cm*50cm=5000cm^2 \\ SA_2=100cm*35cm=3500cm^2 \\ SA_4=100cm*35cm=3500cm^2 \\ SA_5=50cm*35cm=1750cm^2 \\ SA_6=50cm*35cm=1750cm^2 \end{gathered}[/tex]
The surface area of the net is the addition of all of these surface areas:
[tex]\begin{gathered} SA_{net}=(5000+5000+3500+3500+1750+1750)cm^2 \\ SA_{net}=20500cm^2 \end{gathered}[/tex]
