Answer: [tex]P\left(B|A\right)\text{ = 0.68}[/tex]
Explanation:
Given:
P(A) = 0.31
P(B) = 0.48
P(A and B) = 0.21
To find:
P(B|A)
The conditional probability P(B|A) is given as:
[tex]\begin{gathered} P\left(B|A\right)=\text{ }\frac{P(B\text{ and A\rparen}}{P(A)} \\ \\ P\left(B|A\right)=\text{ }\frac{P(A\text{ and B\rparen}}{P(A)} \end{gathered}[/tex][tex]\begin{gathered} P\left(B|A\right)\text{ = }\frac{0.21}{0.31}\text{ = 0.6774} \\ \\ P\left(B|A\right)\text{ = 0.68} \end{gathered}[/tex]
