Given:
In a certain country, the probability that a baby that is born is a boy is 0.52 and the probably that a baby that is born is a girl is 0.48. A family has two children.
Required:
To find the probability that the family has 0, 1, or 2 girls.
Explanation:
Let B=boy and G=girl.
Probability of 2B is,
[tex]\begin{gathered} =(0.52)(0,52) \\ =0.2704 \end{gathered}[/tex]Probability of BG is
[tex]\begin{gathered} =(0.52)(0.48) \\ =0.2496 \end{gathered}[/tex]Probability of GB is the same as the probability of BG, so it is 0.2496.
Probability of 2G is
[tex]\begin{gathered} =(0.48)(0.48) \\ =0.2304 \end{gathered}[/tex]Here is the tree for part (a),
0 child 1st child 2nd child
| -- Boy (27.04%)
_ Boy (52%) -------[
Start | | -- Girl (24.96%)
X -------------------|
| | -- Boy (24.96%)
|_ Girl (48%) --------[
|_ Girl (23.04%)
Final Answer:
0 child 1st child 2nd child
| -- Boy (27.04%)
_ Boy (52%) -------[
Start | | -- Girl (24.96%)
X -------------------|
| | -- Boy (24.96%)
|_ Girl (48%) --------[
|_ Girl (23.04%)
