Solution
For this case we can do the following:
[tex]\frac{3}{x-1}-4=\frac{3-4x+4}{x-1}[/tex][tex]2-\frac{2}{x-1}=\frac{2(x-1)-2}{x-1}[/tex]And if we simplify we got:
[tex]\frac{3-4x+4}{2(x-1)-2}=\frac{7-4x}{2x-2-2}=\frac{7-4x}{2x-4}=\frac{-4x+7}{2(x-2)}[/tex]Final answer would be:
-4x+7 /( 2(x-2))
