Given:
The function f is continuous on the interval [3, 11].
Required:
to find the approximate value f'(9).
Explanation:
The function f(x) is continuous on [3,11].
So
[tex]\begin{gathered} f^{\prime}(9)=\frac{f(10)-f(8)}{10-8} \\ \\ =\frac{16-10}{2} \\ \\ =\frac{6}{2} \\ \\ =3 \end{gathered}[/tex]
Final Answer:
[tex]f^{\prime}(9)=3[/tex]
