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Find the vertex for the parabola whose equation is given by writing the equation in the form y = ax² +bx+c.y=(x-4)²-15(Type an ordered pair.)The vertex is

Respuesta :

Given:

[tex]y=\left(x-4\right)^2-15=x^2-8x+1[/tex]

Required:

To find the vertex.

Answer:

The vertex is given by,

[tex]\begin{gathered} V=(\frac{-b}{2a},\frac{b^2-4ac}{4a}) \\ V=(\frac{8}{2},\frac{64-4}{4}) \\ V=(4,\frac{60}{4}) \\ V=(4,15) \end{gathered}[/tex]

Final Answer:

The oredered pair of vertex(V) is,

[tex]V=(4,15)[/tex]

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