Given:
The dimensions of box are given as:
Length (l) of box (in inches) =
[tex]l=13[/tex]
Width (w) of box (in inches) =
[tex]w=10[/tex]
Height (h) of box (in inches) =
[tex]h=11[/tex]
Required:
To find the surface area of the box.
Explanation:
Let us first convert the dimensions of box into feet.
Length (l) of box (in ft) =
[tex]l=1.08[/tex]
Width (w) of box (in ft) =
[tex]w=0.83[/tex]
Height (h) of box (in ft) =
[tex]h=0.92[/tex]
Thus, the surface area (A) of the box is,
[tex]\begin{gathered} A=2lw+2lh+2wh \\ \Rightarrow A=(2\times1.08\times0.83)+(2\times1.08\times0.92)+(2\times0.83\times0.92) \\ \Rightarrow A=1.7928+1.9872+1.5272 \\ \Rightarrow A=5.3072 \\ \Rightarrow A=5.31 \end{gathered}[/tex]
Final Answer:
The surface area (A) of the box (in sq. ft.) is,
[tex]A=5.31[/tex]
