EXPLANATION:
Given;
We are given a frequency table which displays a survey of numbers of customers that like hamburgers and burritos and those that do not like hamburgers and burritos.
Required;
We are required to analyze the table and use the values to answer the questions that follow.
Solution;
We shall begin by completing the table as follows;
Part A:
What percentage of the survey respondents do not like both burritos and hamburgers?
The percentage that do not like hamburgers is
[tex]Does\text{ }not\text{ }like\text{ }hamburgers=\frac{95}{205}[/tex]
The percentage that do not like burritos is
[tex]Does\text{ }not\text{ }like\text{ }burritos=\frac{135}{205}[/tex]
The percentage that does not like both burritos and hamburgers is;
[tex]\frac{54}{205}=0.263414634146[/tex]
Expressed as a percentage, this is
[tex]\begin{gathered} Percentage=0.263414634146\times100 \\ \\ Percentage=26.3414634146 \\ \\ Percentage=26.34\%\text{ }(rounded\text{ }to\text{ }the\text{ }nearest\text{ }hundredth) \end{gathered}[/tex]
The marginal relative frequency of all customers that like hamburgers is the total of all hamburger lovers divided by the total of all respondents.
[tex]\begin{gathered} Marginal\text{ }relative\text{ }frequency=\frac{hamburger\text{ }lovers}{total\text{ }respondents}=\frac{110}{205} \\ \\ Marginal\text{ }relative\text{ }frequency=0.536585365854 \\ \\ Marginal\text{ }relative\text{ }frequency=53.66\%\text{ }(rounded\text{ }to\text{ }2\text{ }decimal\text{ }places) \end{gathered}[/tex]
ANSWER:
Part (a) 26.34%
Part (b) 53.66%