Given:
a)
we get the points (2,71.2) and (4,166.4) from the table.
Consider the rate of change
[tex]\text{Rate of change =}\frac{y_2-y_1}{x_2-x_1}[/tex][tex]\text{ Substitute }y_2=166.4,y_1=71.2,x_2=4\text{ and }x_1=2,\text{ we get}[/tex]
[tex]\text{Rate of change =}\frac{166.4-71.2}{4-2}[/tex]
[tex]\text{Rate of change =}47.6\text{ meters per second.}[/tex]
The average rate of distance for the distance from 2 seconds to 4 seconds is 47.6 meters per second.
b)
We get the points (6,172.8) and (10, 239.6) from the table.
[tex]\text{Rate of change =}\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\text{ Substitute }y_2=239.6,y_1=172.8,x_2=10\text{ and }x_1=6,\text{ we get}[/tex]
[tex]\text{Rate of change =}\frac{239.6-172.8}{10-6}[/tex]
[tex]\text{Rate of change =}16.7\text{ meters per second.}[/tex]
The average rate of distance for the distance from 6 seconds to 10 seconds is 16.7 meters per second.
