The point of discontinuity of the function f(x) is at x=2
[tex]\begin{gathered} f(x)\text{ =}\frac{x^2+3x-10}{x^2-4}=\text{ }\frac{(x+5)(x-2)}{(x-2)(x+2)\text{ }}=\frac{x+5}{x+2} \\ \text{set x+2 = 0} \\ x=-2 \end{gathered}[/tex]
The horizontal asymptotes is 1
The vertical asymptotes is -2
