You have 2 different savings accounts. For Account A, the simple interest earned after 3months is $0.95. For Account B, the simple interest earned after 15 months is $21.00. If the interestrate is 3.8% for Account A and 2.4% for Account B, how much is the principal in each account? Whichaccount earned you the most interest the first month? Explain your answer.Account A has a principal of $).

Respuesta :

Answer:

• Account A has a principal of $100

,

• Account B has a principal of $700

,

• Account B earned you the most interest in the first month.

Explanation:

Account A

• Simple Interest = $0.95

,

• Time = 3 months = 3/12 years

,

• Interest Rate=3.8%

We know that:

[tex]\begin{gathered} $Simple\: Interest=\frac{Principal X Rate X Time}{100}$ \\ 0.95=\frac{P\times3.8\times\frac{3}{12}}{100} \\ P\times3.8\times\frac{3}{12}=95 \\ 0.95P=95 \\ P=\frac{95}{0.95} \\ P=\$100 \end{gathered}[/tex]

Account B

• Simple Interest = $21

,

• Time = 15 months = 15/12 years

,

• Interest Rate=2.4%

We know that:

[tex]\begin{gathered} $Simple\: Interest=\frac{Principal X Rate X Time}{100}$ \\ 21=\frac{P\times2.4\times\frac{15}{12}}{100} \\ P\times2.4\times\frac{15}{12}=2100 \\ 3P=2100 \\ P=\frac{2100}{3} \\ P=\$700 \end{gathered}[/tex]

Next, we determine the account that earned you the most interest in the first month.

Account A (Interest in the First Month)

[tex]\begin{gathered} $Simple\: Interest=\frac{Principal X Rate X Time}{100}$ \\ =\frac{100\times3.8\times\frac{1}{12}}{100} \\ =\$0.32 \end{gathered}[/tex]

Account B (Interest in the First Month)

[tex]\begin{gathered} $Simple\: Interest=\frac{Principal X Rate X Time}{100}$ \\ =\frac{700\times2.4\times\frac{1}{12}}{100} \\ =\$1.40 \end{gathered}[/tex]

We see that Account B earned you the most interest in the first month.