[tex]\begin{gathered} \\ d=103.9 \end{gathered}[/tex]
Explanation
Step 1
we have a rigth triangle here, then we can use Pythagotas theorem
[tex]side^2_1+side^2_2=hypotenuse^2[/tex]
Let
Step 2
find the sides
side1=60
for side 2
then
[tex]\begin{gathered} side_2^2=60^2+60^2 \\ \text{side}^2_2\text{= 3600+3600} \\ \text{side}_2=\sqrt[]{7200} \end{gathered}[/tex]
Step 3
Let
[tex]\begin{gathered} \text{side}_1=60 \\ \text{side}_2=\sqrt[]{7200} \\ \text{hypotenuse = h} \end{gathered}[/tex]
replace
[tex]\begin{gathered} side^2_1+side^2_2=hypotenuse^2 \\ 60^2+(\sqrt[]{7200})^2=h^2 \\ 3600+7200=h^2 \\ 10800=h^2 \\ h=\sqrt[]{10800}=\text{ 103.92} \\ to\text{ the nearesth tenth } \\ 103.9 \end{gathered}[/tex]
