we can apply the sine function on the angle to get the following:
[tex]\sin (45)=\frac{\text{opposite side}}{hypotenuse}=\frac{x}{5}[/tex]
solving for 'x', we get the following:
[tex]\begin{gathered} \frac{x}{5}=\sin (45) \\ \Rightarrow x=5\cdot\sin (45)=5\cdot\frac{1}{\sqrt[]{2}}=\frac{5}{\sqrt[]{2}} \\ x=\frac{5}{\sqrt[]{2}} \end{gathered}[/tex]
therefore , x = 5/sqrt(2)
