The function h is defined below.x-9h(x)=2x - 5x- 24Find all values of x that are NOT in the domain of h.If there is more than one value, separate them with commas.x = 08x?

we have the function
[tex]h(x)=\frac{x-9}{x^2-5x-24}[/tex]Remember that
The denominator cannot be equal to zero
so
Solve the quadratic equation
[tex]x^2-5x-24=(x+3)(x-8)[/tex]substitute in the original function
[tex]h(x)=\frac{x-9}{(x+3)(x-8)}[/tex]therefore
The domain of the given function is the interval
(-infinite,-3) U (-3,8) U (8, infinite)