The N₂(g) at 1.00 atm and 25.0° C are produced by the decomposition of 150. g of NaN3 is 84.7 L.
Decomposition or rot is the procedure by which dead organic materials are broken down into simpler organic or inorganic be counted such as carbon dioxide, water, easy sugars, and mineral salts.
Molar mass of NaN3 = 23 + 3(14) = 65 g/mol
Mass of NaN3 = 150.
Number of moles of NaN3 = mass / molar mass
n = 150. / 65
n= 2.31 mol of NaN3
From the balanced equation,
2 mol NaN3 produces 3 mol N2
Then, 2.31 mol NaN3 produces 2.31 × 3 / 2 = 3.46 mol N2
Assuming the ideal gas equation,
V = n RT / p
V = 3.46 * 0.0821 * 298.15 / 1.00
V = 84.7 L
Learn more about decomposition here:-https://brainly.com/question/27300160
#SPJ9
