Taking into account the reaction stoichiometry, 159.28 grams of NH₃ are formed from 4.42 moles of N₂ and excess H₂.
In first place, the balanced reaction is:
N₂ + 3 H₂ → 2 NH₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
The molar mass of the compounds is:
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
The following rule of three can be applied: if by reaction stoichiometry 1 mole of N₂ form 34 grams of NH₃, 4.42 moles of N₂ form how much mass of NH₃?
[tex]mass of NH_{3} =\frac{4.42 moles of N_{2}x34 grams of NH_{3} }{1 mole of N_{2}}[/tex]
mass of NH₃= 159.28 grams
Then, 159.28 grams of NH₃ are formed from 4.42 moles of N₂ and excess H₂.
Learn more about the reaction stoichiometry:
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