The initial amount in the sample and the amount remaining after 40 hours are 2400 grams and 331 grams respectively.
From the information given, we have the function to be;
a(t)=2400(1/2)^t/14
Where
To determine the initial amount, we have that t = 0
Substitute into the function, we have
[tex]A(t) = 2400[/tex] × [tex]\frac{1}{2} ^\frac{0}{14}[/tex]
[tex]A (t) = 2400[/tex] × [tex]\frac{1}{2} ^0[/tex]
[tex]A (t) = 2400[/tex]
The initial amount is 2400 grams
For the amount remaining after 40 years, t = 40 years
A(t)=2400(1/2)^t/14
Substitute into the function, we have
[tex]A(t) = 2400[/tex] × [tex]\frac{1}{2} ^\frac{40}{14}[/tex]
[tex]A(t) = 2400[/tex] × [tex](0. 5) ^2^.^8^5^7[/tex]
[tex]A(t) = 2400[/tex] × [tex]0. 1380[/tex]
A(t) = 331. 26
A(t) = 331 grams in the nearest gram
Thus, the initial amount in the sample and the amount remaining after 40 hours are 2400 grams and 331 grams respectively.
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