The radioactive substance uranium-240 has a half-life of 14 hours. The amount At of a sample of uranium-240 remaining (in grams) after t hours is given by the following exponential function.

a(t)=2400(1/2)^t/14

Find the initial amount in the sample and the amount remaining after 40 hours.
Round your answers to the nearest gram as necessary.

Respuesta :

The initial amount in the sample and the amount remaining after 40 hours are 2400 grams and 331 grams respectively.

How to determine the amount

From the information given, we have the function to be;

a(t)=2400(1/2)^t/14

Where

  • a(t) is the final amount
  • t represents time
  • 'I4' is the half life of the radioactive substance, Uranium - 240

To determine the initial amount, we have that t = 0

Substitute into the function, we have

[tex]A(t) = 2400[/tex] × [tex]\frac{1}{2} ^\frac{0}{14}[/tex]

[tex]A (t) = 2400[/tex]  × [tex]\frac{1}{2} ^0[/tex]

[tex]A (t) = 2400[/tex]

The initial amount is 2400 grams

For the amount remaining after 40 years, t = 40 years

A(t)=2400(1/2)^t/14

Substitute into the function, we have

[tex]A(t) = 2400[/tex] × [tex]\frac{1}{2} ^\frac{40}{14}[/tex]

[tex]A(t) = 2400[/tex] × [tex](0. 5) ^2^.^8^5^7[/tex]

[tex]A(t) = 2400[/tex] × [tex]0. 1380[/tex]

A(t) = 331. 26

A(t) = 331 grams in the nearest gram

Thus, the initial amount in the sample and the amount remaining after 40 hours are 2400 grams and 331 grams respectively.

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