The price that will maximize company’s revenue of $10,000 is $50.
From the information, the company determines 50that the revenue, in dollars, for selling a particular model of lamp is given by R(x)=x(−20x+1200),
Therefore, this will be:
R(x) = -20x² + 1200x
10000 = -20x² + 1200x
-20x² + 1200x - 10000 = 0
x² - 60x + 500
x² - 50x - 10x + 500
x(x - 50) - 10(x - 50)
(x - 50)(x - 10)
Therefore, x - 50 = 0
x = 0 + 50 = 50
The price is 50.
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