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The probability that the value of p(x) is greater than 315 is 0.063754

How to determine the probability that the value of p(x) is greater than 315?

From the question, the given parameters about the distribution are

  • Mean value of the set of data = 283
  • Standard deviation value of the set of data = 21
  • The actual data value = 315

The z-score of the data value is calculated using the following formula

z = (x - mean value)/standard deviation

Substitute the given parameters in the above equation

z = (315 - 283)/21

Evaluate the difference of 315 and 283

z = 32/21

Evaluate the quotient of 32 and 21

z = 1.524

The probability that the value of p(x) is greater than 315 is then calculated as:

P(x > 315) = P(z > 1.524)

From the z table of probabilities, we have;

P(x > 315) = 0.063754

Hence, the probability that the value of p(x) is greater than 315 is 0.063754

Read more about probability at:

brainly.com/question/25870256

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