Respuesta :
Proportion of the population will be heterozygous is 0.48
Let's start with the basic Hardy-Weinberg equations first.
p + q = 1 and p^2 + 2pq + q^2 = 1
With "p" being the dominant allele and "q" being the recessive allele
We know that 16% (or 0.16) show the recessive trait. This means that the fraction of the population with the recessive trait, q^2 is 0.16
With the value for q^2, q can be calculated
What follows is that q = 0.4
With this knowledge "p" can be calculated 1 - q= p
which results in "p" being 0.6
This 0.6 is the frequency at which the dominant allele is present in the population
heterozygous = 2pq = 2 (0.6 x 0.4) = 0.48
Hence, proportion of the population will be heterozygous is 0.48
Learn more about Hardy-weinberg principle here:
https://brainly.com/question/1365714
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