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sciencebiologybiology questions and answersin silkmoths (bombyx mori), red eyes (re) and white-banded wings (wb) are encoded by two mutant alleles that are recessive to those that produce wild-type traits (re+and wb+); these two genes are on the same chromosome. a moth homozygous for red eyes and white-banded wings is crossed with a moth homozygous for the wild-type traits. the f1 have normal eyes
Question: In Silkmoths (Bombyx Mori), Red Eyes (Re) And White-Banded Wings (Wb) Are Encoded By Two Mutant Alleles That Are Recessive To Those That Produce Wild-Type Traits (Re+And Wb+); These Two Genes Are On The Same Chromosome. A Moth Homozygous For Red Eyes And White-Banded Wings Is Crossed With A Moth Homozygous For The Wild-Type Traits. The F1 Have Normal Eyes
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In silkmoths (Bombyx mori), red eyes (re) and white-banded wings (wb) are encoded by two mutant alleles that are recessive to those that produce wild-type traits (re+and wb+); these two genes are on the same chromosome. A moth homozygous for red eyes and white-banded wings is crossed with a moth homozygous for the wild-type traits. The F1 have normal eyes and normal wings. The F1 are crossed with moths that have red eyes and white-banded wings in a testcross. The progeny of this testcross are

wild-type eyes, wild-type wings

418

red eyes, wild-type wings

19

wild-type eyes, white-banded wings

16

red eyes, white-banded wings

426

a. What phenotypic proportions would be expected if the genes for red eyes and for white-banded wings were located on different chromosomes?

b. What is the rate of recombination between the genes for red eyes and those for white-banded wings

Question

28-07-2022
Biology

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Find solutions for your homework
Find solutions for your homework

sciencebiologybiology questions and answersin silkmoths (bombyx mori), red eyes (re) and white-banded wings (wb) are encoded by two mutant alleles that are recessive to those that produce wild-type traits (re+and wb+); these two genes are on the same chromosome. a moth homozygous for red eyes and white-banded wings is crossed with a moth homozygous for the wild-type traits. the f1 have normal eyes
Question: In Silkmoths (Bombyx Mori), Red Eyes (Re) And White-Banded Wings (Wb) Are Encoded By Two Mutant Alleles That Are Recessive To Those That Produce Wild-Type Traits (Re+And Wb+); These Two Genes Are On The Same Chromosome. A Moth Homozygous For Red Eyes And White-Banded Wings Is Crossed With A Moth Homozygous For The Wild-Type Traits. The F1 Have Normal Eyes
This problem has been solved!

See the answer
In silkmoths (Bombyx mori), red eyes (re) and white-banded wings (wb) are encoded by two mutant alleles that are recessive to those that produce wild-type traits (re+and wb+); these two genes are on the same chromosome. A moth homozygous for red eyes and white-banded wings is crossed with a moth homozygous for the wild-type traits. The F1 have normal eyes and normal wings. The F1 are crossed with moths that have red eyes and white-banded wings in a testcross. The progeny of this testcross are

wild-type eyes, wild-type wings

418

red eyes, wild-type wings

19

wild-type eyes, white-banded wings

16

red eyes, white-banded wings

426

a. What phenotypic proportions would be expected if the genes for red eyes and for white-banded wings were located on different chromosomes?

b. What is the rate of recombination between the genes for red eyes and those for white-banded wings

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jayilych4real jayilych4real · Answer 1 · 2022-07-28T23:03:14+02:00

The phenotypic proportions which would be expected if the genes for red eyes and for white-banded wings were located on different chromosomes are:

(a)

1⁄4 wild-type eyes, wild-type wings
1⁄4 red eyes, wild-type wings
1⁄4 wild-type eyes, white-banded wings
1⁄4 red eyes, white-banded wings

What is the distance and rate of recombination?

The distance between the genes is four map units.

The rate of recombination between the genes for red eyes and those for white-banded wings is 4%.

(b)

The F1 heterozygote inherited a chromosome with alleles for red eyes and white-banded wings (re wb) from one parent and a chromosome with alleles for wild-type eyes and wild-type wings (re+ wb+) from the other parent. These are therefore the phenotypes of the nonrecombinant progeny, present in the highest numbers. The recombinants are the 19 with red eyes, wild-type wings and 16 with wild-type eyes, and white-banded wings.

RF = recombinants/total progeny × 100% = (19 + 16)/879 × 100% = 4.0%