The trigonometry ratios are cos(θ) = -7/√58, sec(θ) = -√58/7 and cot(θ) = -7/3
How to determine the trigonometry ratios?
The point on the terminal side is given as:
(x, y) = (-7, 3)
Start by calculating the hypotenuse using:
[tex]h= \sqrt{x^2 + y^2[/tex]
So, we have:
[tex]h= \sqrt{(-7)^2 + 3^2[/tex]
Evaluate
[tex]h= \sqrt{58[/tex]
The cosine is then calculated using:
cos(θ) = x/h
This gives
cos(θ) = -7/√58
The secant is then calculated using:
sec(θ) = 1/cos(θ)
This gives
sec(θ) = -√58/7
The cotangent is then calculated using:
cot(θ) = cos(θ)/sin(θ)
Where
sin(θ) = y/h
So, we have:
sin(θ) = 3/√58
So, we have:
cot(θ) = (-7/√58)/(3/√58)
This gives
cot(θ) = -7/3
Read more about terminal points at:
https://brainly.com/question/1621860
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