Respuesta :
The number of moles of gas lost is Ā 0.0213 mol. It can be solved with the help of Ideal gas law.
What is Ideal law ?
According to this law, "the volume of a given amount of gas is directly proportional to the number on moles of gas, directly proportional to the temperature and inversely proportional to the pressure. i.e.
PV = nRT.
Where,
- p = pressure
- V = volume (1.75 L = 1.75 x 10ā»Ā³ m³)
- T = Ā absolute temperature
- n = number of moles
- R = Ā gas constant, 8.314 J*(mol-K)
Therefore, the number of moles is
n = PV / RT
State 1 :
- Tā = (25ā° C = 25+273 = 298 K)
- pā = 225 kPa = 225 x 10³ N/m²
State 2 :
- Tā = 10 C = 283 K
- pā = 185 kPa = 185 x 10³ N/m²
The loss in moles of gas from state 1 to state 2 is
Īn = V/R (Pā/Tā - Pā/Tā )
V/R = (1.75 x 10ā»Ā³ m³)/(8.314 (N-m)/(mol-K) = 2.1049 x 10ā»ā“ (mol-m²-K)/N
pā/Tā = (225 x 10³)/298 = 755.0336 N/(m²-K)
pā/Tā = (185 x 10³)/283 = 653.7102 N/(m²-K)
Therefore,
Īn = (2.1049 x 10ā»ā“ (mol-m²-K)/N)*(755.0336 - 653.7102 N/(m²-K))
Ā Ā = 0.0213 mol
Hence, The number of moles of gas lost is 0.0213 mol.
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