The equation for the overall reaction obtained by adding these equations is; 2NO₂(g) ⇒ N₂O₄(g)
We are given equations;
2NO₂(g) ----> 2NO(g) + O₂(g) ---(1)
2NO(g) -----> N₂(g) + O₂(g) -----(2)
N₂(g) + 2O₂(g) ----> N₂O₄(g) -----(3)
Add eq 1 and eq 2 to get;
2NO₂(g) + 2NO(g) ⇒ 2NO(g) + O₂(g) + N₂(g) + O₂(g)
2NO will cancel out to get;
2NO₂(g) ⇒ N₂(g) + 2O₂(g) -----(4)
Add eq 3 to eq 4 to get;
N₂(g) + 2O₂(g) + 2NO₂(g) ⇒ N₂O₄(g) + N₂(g) + 2O₂(g)
This will reduce to;
2NO₂(g) ⇒ N₂O₄(g)
The correct question is;
Consider the chemical equations shown here.
2NO₂(g) ----> 2NO(g) + O₂(g)
2NO(g) -----> N₂(g) + O₂(g)
N₂(g) + 2O(g) ----> N₂O₄(g)
What is the equation for the overall reaction obtained by adding these equations?
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