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45.8 grams of copper requires 1172 J of heat to reach a final temperature of 100.5 ℃. What was the initial temperature? Specific heat of copper is 0.385 J/g℃. (7.02)
A. 66.5[?][?][?]
B. 122[?][?][?]
C. 34.0[?][?][?]
D. 75.2[?][?][?]

I also have no idea what the [?][?][?] is. Can someone please help me for 25 points? :'(

Respuesta :

amandamcbackup

Answer: Option A, 66.5

Explanation:

So you want to use the heat capacity formula

So, q(heat)=m(mass) * cp (specific heat) * DeltaT (change in temp)

so m=45.8, cp =0.385, q=1172

you dont have the final temp for DeltaT so you have to fill in and divide

1172 = (45.8) * (0.385) * Delta T

1172 = 17.633 * DeltaT (Now divide)

1172/17.633 = Delta T

66.46 = Delta T, rounded you get 66.5 or option A

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