Respuesta :
Answer:
B) 2y² - y - 6 = 0
Given following:
- x = y² - 1 ___equation 1
- 2x - y = 4 ___equation 2
Insert equation 1 into 2:
- 2(y² - 1) - y = 4
- 2y² - 2 - y = 4
- 2y² - y - 2 - 4 = 0
- 2y² - y - 6 = 0
Answer:
B) 2y² - y - 6 = 0
Given following:
Insert equation 1 into 2: