Answer:
A and C.
Step-by-step explanation:
We are given that: "The square of a number (which we can call x) is three less than four times the number."
In other words:
[tex]\displaystyle x^2 = 4x - 3[/tex]
Hence solve for x by isolating the equation and factoring:
[tex]\displaystyle \begin{aligned} x^2 - 4x + 3 & = 0 \\ \\ (x-1)(x-3) & = 0 \\ \\ x & = 1 \text{ or } x = 3 \end{aligned}[/tex]
In conclusion, our answers are A and C.
