The solution to the trigonometry identity is -sin^2(x) + sin(x) + 1 = -sin(x)
What is sine and the cosecant trigonometry function?
In trigonometry functions, the cosecant(csc) appears to be the reciprocal of the sine function.
- The trigonometry formula for sine is = opposite/hypotenuse,
- Thus the cosecant(csc) will be hypotenuse/opposite.
Given that:
[tex]\mathbf{1- \dfrac{sin^2(x)}{1}+sin(x)=\dfrac{-1}{csc(x)}}[/tex]
[tex]\mathbf{- \dfrac{sin^2(x)}{1}+sin(x)=\dfrac{-1}{csc(x)}}[/tex]
[tex]\mathbf{- \dfrac{sin^2(x)}{2}+sin(x)+ \dfrac{cos^2x}{2}+\dfrac{1}{2}=-sin(x)}[/tex]
[tex]\mathbf{- sin^2(x)+sin(x)+1 = -sin (x)}[/tex]
Learn more about calculating trigonometry functions here:
https://brainly.com/question/1143565
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