The amount of a sample remaining after t days is given by the equation p(1) - al2 is: 74 days.
Using this formula
P(t)=A×(1/2)^t/h
Let plug in the formula
0.6x=x ×(1/2)^t/h
0.6=(1/2)^t/100
Hence:
Log0.6=Log(1/2)^t/100
Log 0.6=t/100× log0.5
Log 0.6/Log0.5×100=t
-0.2218487/-0.30102999×100=t
0.736×100=t
t=73.6
t=74 days (Approximately)
The amount of a sample remaining after t days is: 74 days.
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