Consider the line y=-2/3x+9 . Find the equation of the line that is parallel to this line and passes through the point (-8,3) . Find the equation of the line that is perpendicular to this line and passes through the point (-8,3) .

Respuesta :

The equation of line which is parallel to line is y = (-2x-7)/3.

What is Gradient?

Gradient is the ratio between change in y-axis to change in x-axis.

Here, Given Equation of line is y = [tex]\frac{-2}{3}x+9[/tex]

gradient of line m₁ = -2/3

Equation of line passing through point (-8, 3) and gradient -2/3 (parallel to given line) is

(y - y₁) = m₂(x - x₁)

( y - 3) = -2/3(x+8)

3y - 9 = -2x -16

3y = -2x -16 + 9

3y = -2x -7

y = (-2x-7)/3

Thus, the equation of line which is parallel to line is y = (-2x-7)/3

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