See below for the proof of the equation 4h² - 4dh + x² = 0 using the Pythagoras theorem
How to prove the equation?
The Pythagoras theorem states that:
Hypotenuse² = Opposite² + Adjacent²
The question is incomplete, as the figure is not given.
So, I will complete the proof using the following parameters:
- Hypotenuse = 2√dh
- Opposite = x
- Adjacent = 2h
Substitute the above values in the following equation
Hypotenuse² = Opposite² + Adjacent²
So, we have:
(2√dh)² = x² + (2h)²
Evaluate the exponents
4dh = x² + 4h²
Subtract 4dh from both sides
0 = x² + 4h² - 4dh
Rewrite as:
4h² - 4dh + x² = 0
Hence, the equation has been proved
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