exceed69
exceed69
29-05-2022
Mathematics
contestada
i want to know this factorization
Respuesta :
colinspurdle
colinspurdle
29-05-2022
Here is one factorisation
32 - (8b^4)^-1 = (1/2)(64 - (4b^4)^-1) = (1/2)(8 + (2b^2)^-1)(8 - (2b^2)^-1)
Or even
32 - (8b^4)^-1 = (1/8)(256 - b^-4) = (1/8)(16 + b^-2)(16 - b^-2)
Both use the difference of two squares ie a^2 - b^2 = (a + b)(a - b)
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