The volume of nitric oxide that will diffuse out of the partition in 10 seconds when methane diffuses is 62.5 mL
This is defined as the amount diffused per unit time. Mathematically, it can be expressed as
Rate = volume / time
Rate = volume / time
Rate = 25 / 4
Rate = 6.25 mL/s
Rate = volume / time
6.25 = volume of nitric oxide / 10
Cross multiply
Volume of nitric oxide = 6.25 × 10
Volume of nitric oxide = 62.5 mL
Learn more about rates of diffusion:
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