Two great structures are
described below. What is the
difference, in square feet, between the visible
surface area of
the Great Pyramid and the first tower of the World Trade
Center? (Hint: The bottom side is not visible for either
structure.)
On September 11, 2001,
terrorists crashed planes
The Great Pyramid of
Giza, built around 2550
B.C., has a square base
with a length of 756 feet,
and the distance from
the middle of any base
side to the top is 612 feet.
into the World Trade
Center Twin Towers. The
first tower was a
rectangular prism with a
square base whose sides
were 208 feet long. The
tower was 1,368 feet tall.

Respuesta :

The difference, in square feet, between the visible surface area of

The Great Pyramid and the first tower of the World Trade Center are 358704.

What is the lateral surface area of this rectangular prism?

A rectangular prism is a three-dimensional shape that has two at the top and bottom and four are lateral faces.

The lateral surface area of this rectangular prism = Perimeter x height

The Great Pyramid of Giza, has a square base with a length of 756 feet, and the distance from the middle of any base side to the top is 612 feet.

The first tower was a rectangular prism with a square base whose sides

were 208 feet long. The tower was 1,368 feet tall.

Total surface area = base area + (1/2 × perimeter × slant height)

Perimeter of base = 4 × 756 = 3024 feet

Slant height = 612 feet

Base area = 756² = 571536 feet²

The total surface area

[tex]= 571536 + (1/2 \times 3024 \times 612)\\ 1496880 feet^2[/tex]

The surface area of this rectangular prism = Perimeter x height

Perimeter of base = 4 × 208 = 832 feet

Area = [tex]832 \times 1368\\\\1138176[/tex]

The difference, in square feet, between the visible surface area of

the Great Pyramid and the first tower of the World Trade Center are 358704.

Learn more about the area;

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