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A body travels a distance of 20m in the 7th second and 24m in the 9th second. How much distance shall it travel in the 15th second?

Respuesta :

Answer:

36 m

Explanation:

We can consider this to be an AP.

Then,

  • a₇ = 20
  • a₉ = 24

Subtract a₇ from a₉.

  • a + 8d - a + 6d = 24 - 20
  • 2d = 4
  • d = 2

  • a + 6(2) = 20
  • a = 8

Finding a₁₅

  • a₁₅ = a + 14d
  • a₁₅ = 8 + 14(2)
  • a₁₅ = 8 + 28
  • a₁₅ = 36 m
  • f(7)=20
  • f(9)=24

Find rate of change

  • f(9)-f(7)/9-7
  • 24-20/9-7
  • 4/2
  • 2m/s

So

Distance travel in 6 s

  • Speed×Time
  • 6(2)
  • 12m

Distance in 15s:-

  • 12+24
  • 36m

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