Answer:
[tex]\textsf{C)}\quad 3x-45=10[/tex]
Step-by-step explanation:
Given equation:
[tex]\dfrac15x-3=\dfrac23[/tex]
Multiply both sides by 3:
[tex]\implies 3\left(\dfrac15x-3\right)=\dfrac23 \cdot 3[/tex]
[tex]\implies \dfrac{3 \cdot 1}{5}x-3 \cdot 3=\dfrac{2 \cdot 3}{3}[/tex]
[tex]\implies \dfrac35x-9=2[/tex]
Multiply both sides by 5:
[tex]\implies 5\left(\dfrac35x-9\right)=2 \cdot 5[/tex]
[tex]\implies \dfrac{5 \cdot 3}{5}x-5 \cdot 9=10[/tex]
[tex]\implies 3x-45=10[/tex]
