Answer:
{2;-1;1}.
Step-by-step explanation:
it is possible to make up the system of three equations:
a) g(0)=1: c=1;
b) g(1)=2: a+b+c=2;
c) g(-1)=4: a-b+c=4;
2) the system has the only solution:
[tex]\left[\begin{array}{ccc}c=1\\a+b+c=2\\a-b+c=4\end{array} \ = > \ \left[\begin{array}{ccc}a= 2\\b=-1\\c=1\end{array}[/tex]
4) finally, a=2; b=-1 and c=1.
