A block is pushed against the spring with spring constant 15 kN/m (located on the lefthand side of the track) and compresses the spring a distance 5 cm from its equilibrium position (as shown in the figure below). The block starts at rest, is accelerated by the compressed spring, and slides across a frictionless track (as shown in the figure below). It leaves the track horizontally, flies through the air, and subsequently strikes the ground. The acceleration of gravity is 9.81 m/s

a) What is the speed v of the block when it
leaves the track?
Answer in units of m/s.
b) What is the horizontal distance x the block
travels in the air?
Answer in units of m
c) What is the total speed of the block when it
hits the ground?
Answer in units of m/s

Respuesta :

Answer:

F = -K x = 15 kN/m " .05 m = .75 kN = 750 N

W = 1/2 K X^2        original potential energy of block

W = 1/2 * 15 Kn/m * .0025 m^2 = 18.75 J

One cannot calculate speed of block without knowing mass of block.