just5johnson
just5johnson
30-01-2017
Mathematics
contestada
Solve equation for 0 < x < 2pi
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LammettHash
LammettHash
30-01-2017
[tex]\sqrt2\cos x-1=0[/tex]
[tex]\sqrt2\cos x=1[/tex]
[tex]\cos x=\dfrac1{\sqrt2}[/tex]
This occurs twice in the interval [tex]0\le x\le2\pi[/tex], when [tex]x=\dfrac\pi4[/tex] and [tex]x=\dfrac{3\pi}4[/tex].
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