how many sodium ions are in 3.0 moles of nacl

1 molecule of NaCl contains 1 sodium ion (Na+), that's why if we have 3.0 moles of.
NaCl, we have 3.0 moles of Na+.
N(ions) = n(mol) · NA.
N(ions) = 3.0 moles · 6.02·1023 = 18.06 ·1023 ions.

Answer Link

Eduard22sly Eduard22sly · Answer 2 · 2021-11-12T14:30:18+01:00

The number of sodium ion, Na⁺ present in 3 moles of NaCl is 1.806×10²⁴ ions

We'll begin by writing the balanced dissociation equation for NaCl. This can be written as follow:

NaCl(aq) —> Na⁺(aq) + Cl¯(aq)

From the balanced equation above,

1 mole of NaCl contains 1 mole of Na⁺

Therefore,

3 moles of NaCl will also contain 3 moles of Na⁺

Thus, 3 moles of Na⁺ are present in 3 moles of NaCl

Finally, we shall determine the number of ions in 3 moles of Na⁺. This can be obtained as follow:

From Avogadro's hypothesis,

1 mole of Na⁺ = 6.02×10²³ ions

Therefore,

3 moles of Na⁺ = 3 × 6.02×10²³

3 moles of Na⁺ = 1.806×²⁴ ions

Thus, the number of sodium ion in 3 moles of NaCl is 1.806×10²⁴ ions

Learn more: https://brainly.com/question/14295820