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Three resistors with resistances of 4.0, 6.0, and 10 ohms are connected in series. what is the equivalent resistance of this combination of resistors?
a. 1.9 ohms
b. 9.2 ohms
c. 20 ohms
d. 40 ohms

Respuesta :

niamhcaley
in series = Rt = R1 + R2 + R3 and so on

therefore Rt = 4.0Ω + 6.0Ω + 10.0Ω

Rt = 20.0Ω

Answer:

20 ohms

Explanation:

4 ohms + 6 ohms + 10 ohms = 20 ohms

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