Answer:
A
Step-by-step explanation:
tanΘ = [tex]\frac{\sqrt{3} }{3}[/tex] , then
Θ = [tex]tan^{-1}[/tex] ( [tex]\frac{\sqrt{3} }{3}[/tex] ) = [tex]\frac{\pi }{6}[/tex]
since tanΘ > 0 then Θ is in first / third quadrants
Θ = π + [tex]\frac{\pi }{6}[/tex] = [tex]\frac{7\pi }{6}[/tex]
solution is { [tex]\frac{\pi }{6}[/tex] , [tex]\frac{7\pi }{6}[/tex] } in the interval 0 < Θ < 2π
