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How many grams of aluminum oxide will you need to start with in order to make 6500 g of aluminum hydroxide?

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Answer:

Explanation:

2Al(s) + 3 2 O2(g) → Al2O3(s) And given the stoichiometry ...and EXCESS dioxygen gas...we would get 6.25⋅ mol of alumina. the which represents a mass... ...6.25 ⋅ mol ×101.96 ⋅ g ⋅ mol−1 molar mass of alumina ≡ 637.25 ⋅ g.

cherryjoycervantes

Answer:

56.7 grams of aluminum oxide (AI²O³) are produced.Need a fast expert's response.

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